vxworks for x86读取bios时间的解决方法

时间:2014-07-22 23:04:35   收藏:0   阅读:844

vxworks for x86读取bios时间的解决方法

 系统时间与bsp有关,在vzworks for x86系列的目标没有直接读取RTC(实时时钟控制器)的函数,用time.h中的函数读到的始终是 00:00:00, Jan. 1 1970.

  所以在x86系列的机器中,我们可以从bios中读取当前的时钟。用sysInByte(),sysOutByte(),在70,和71端口读取或写bios里的时间.

  首先要分析bios的内容,找出秒,分,时,天,月,年的存放地址。

他们分别是: 0x00,0x02,0x04,0x07,0x08,0x09

然后从71端口读出相应的值,进行转换。

如:秒

  sysOutByte(0x70,0x00);

  second = sysInByte(0x71);

读出的second进行转换,:

  second = (second &0x0F) + 10*((second &0xF0)>>4);

示例代码:

time_t biostime()

{

  struct tm   ahora;

  unsigned char cHour, cMin, cSec;

  unsigned char cDay, cMonth, cYear;

  sysOutByte(0x70,0x00/*second*/);

  cSec = sysInByte(0x71);

  ahora.tm_sec = (cSec&0x0F) + 10*((cSec&0xF0)>>4);

  sysOutByte(0x70,0x02/*minut*/);

  cMin = sysInByte(0x71);

  ahora.tm_min = (cMin&0x0F) + 10*((cMin&0xF0)>>4);

  sysOutByte(0x70,0x04/*hour*/);

  cHour = sysInByte(0x71);

  ahora.tm_hour = (cHour&0x0F) + 10*((cHour&0xF0)>>4);

 

  sysOutByte(0x70,0x07/*day*/);

  cDay = sysInByte(0x71);

  ahora.tm_mday = (cDay&0x0F) + 10*((cDay&0xF0)>>4);

  sysOutByte(0x70,0x08/*month*/);

  cMonth = sysInByte(0x71);

  ahora.tm_mon = (cMonth&0x0F) + 10*((cMonth&0xF0)>>4) - 1;

  sysOutByte(0x70,0x09/*year*/);

  cYear = sysInByte(0x71);

  ahora.tm_year = 100 + (cYear&0x0F) + 10*((cYear&0xF0)>>4);

  return mktime(&ahora);

}

我们在系统初始化时读取bios时间一次,然后修改系统时钟:

 clock_settime(..)

以后我们得到的时间就都是当前的正确时间

示例:

void inittime()

{

  int res;

  struct timespec ts;

  struct tm daytime;

  time_t stime;

  ts.tv_sec = biostime();

  ts.tv_nsec = 0;

  res = clock_settime(CLOCK_REALTIME, &ts);

 

  stime = time(NULL);

 

  daytime = *localtime(&stime);

  printf ( "time is :%s\n", asctime(&daytime) );

}

vxworks for x86读取bios时间的解决方法,码迷,mamicode.com

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