Path Sum II
时间:2015-01-30 22:56:04
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Given a binary tree and a sum, find all root-to-leaf paths where each path‘s sum equals the given sum.
For example:Given the below binary tree and
sum
= 22
,
5 / 4 8 / / 11 13 4 / \ / 7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]
class Solution { public: vector<vector<int> > sumpath; void getPath(TreeNode *root, int cursum, int sum, vector<int> &path) { if(root == NULL) return; path.push_back(root->val); cursum += root->val; if(cursum == sum && root->left == NULL && root->right == NULL) sumpath.push_back(path); getPath(root->left, cursum, sum, path); getPath(root->right, cursum, sum, path); cursum -= root->val; path.pop_back(); } vector<vector<int> > pathSum(TreeNode *root, int sum) { vector<int> path; getPath(root, 0, sum, path); return sumpath; } };
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