[leetcode]Path Sum @ Python

时间:2014-05-26 18:37:11   收藏:0   阅读:295

原题地址:https://oj.leetcode.com/problems/path-sum/

题意:

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,

              5
             /             4   8
           /   /           11  13  4
         /  \              7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

解题思路:使用递归解决。

代码:

bubuko.com,布布扣
# Definition for a  binary tree node
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution:
    # @param root, a tree node
    # @param sum, an integer
    # @return a boolean
    def hasPathSum(self, root, sum):
        if root == None:
            return False
        if root.left == None and root.right == None:
            return root.val == sum
        return self.hasPathSum(root.left, sum - root.val) or self.hasPathSum(root.right, sum - root.val)
bubuko.com,布布扣

 

[leetcode]Path Sum @ Python,布布扣,bubuko.com

评论(0
© 2014 mamicode.com 版权所有 京ICP备13008772号-2  联系我们:gaon5@hotmail.com
迷上了代码!