微信lbs---返回两个经纬度坐标点的距离
时间:2014-05-26 02:11:13
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微信开发:lbs附近的商家,在数据库里记录商家的坐标,lbs设置里管理搜索半径,查询的时候,查询
客户当前坐标的半径内的所有商家列表。
个人喜欢不一样,我选择了执行sql
,毕竟效果高点。微信开发必须得将就效率问题。不然等半天出不来,急死人,半天出不来结果,客户直接走人。
不多说,直接上代码
\\返回两个经纬度坐标点的距离(单位:米) \\C# 方法 ///<summary>返回两个经纬度坐标点的距离(单位:米) by Alex.Y</summary> ///<param name="Longtiude">来源坐标经度Y</param> ///<param name="Latitude">来源坐标经度X</param> ///<param name="Longtiude2">目标坐标经度Y</param> ///<param name="Latitude2">目标坐标经度X</param> ///<returns>返回距离(米)</returns> public double getMapDistance( double Longtiude, double Latitude, double Longtiude2, double Latitude2) { var lat1 = Latitude; var lon1 = Longtiude; var lat2 = Latitude2; var lon2 = Longtiude2; var earthRadius = 6371; //appxoximate radius in miles 6378.137 var factor = Math.PI / 180.0; var dLat = (lat2 - lat1) * factor; var dLon = (lon2 - lon1) * factor; var a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) + Math.Cos(lat1 * factor) * Math.Cos(lat2 * factor) * Math.Sin(dLon / 2) * Math.Sin(dLon / 2); var c = 2 * Math.Atan2(Math.Sqrt(a), Math.Sqrt(1 - a)); double d = earthRadius * c * 1000; return d; } --返回两个经纬度坐标点的距离(单位:千米) -- ============================================= -- Author: alex.Y -- Create date: getdate() -- Description: 返回两个经纬度坐标点的距离(单位:千米) -- ///<param name="@LngBegin">来源坐标经度Y</param> -- ///<param name="@LatBegin">来源坐标经度X</param> -- ///<param name="@LngEnd">目标坐标经度Y</param> -- ///<param name="@LatEnd">目标坐标经度X</param> -- ============================================= CREATE FUNCTION [dbo].[ufn_GetMapDistance] (@LngBegin REAL, @LatBegin REAL, @LngEnd REAL, @LatEnd REAL) RETURNS FLOAT AS BEGIN --距离(千米) DECLARE @Distance REAL DECLARE @EARTH_RADIUS REAL --SET @EARTH_RADIUS =6378.137 SET @EARTH_RADIUS =6371 DECLARE @RadLatBegin REAL, @RadLatEnd REAL, @RadLatDiff REAL, @RadLngDiff REAL SET @RadLatBegin = @LatBegin *PI()/ 180.0 SET @RadLatEnd = @LatEnd *PI()/ 180.0 SET @RadLatDiff = @RadLatBegin - @RadLatEnd SET @RadLngDiff = @LngBegin *PI()/ 180.0 - @LngEnd *PI()/ 180.0 SET @Distance = 2 *ASIN( SQRT( POWER(SIN(@RadLatDiff / 2), 2)+COS(@RadLatBegin)*COS(@RadLatEnd) *POWER(SIN(@RadLngDiff / 2), 2) ) ) SET @Distance = @Distance * @EARTH_RADIUS --SET @Distance = Round(@Distance * 10000) / 10000 RETURN @Distance -- SELECT [dbo].[ufn_GetMapDistance](116.3130497932434100,39.9804086267150800,116.3731849193573000,39.9110159284269700) END |
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