每日LeetCode - 122. 买卖股票的最佳时机 II(C语言)
时间:2021-06-11 18:18:14
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C语言
int maxProfit(int* prices, int pricesSize) { int dp[pricesSize][2]; dp[0][0] = 0, dp[0][1] = -prices[0]; for (int i = 1; i < pricesSize; ++i) { dp[i][0] = fmax(dp[i - 1][0], dp[i - 1][1] + prices[i]); dp[i][1] = fmax(dp[i - 1][1], dp[i - 1][0] - prices[i]); } return dp[pricesSize - 1][0]; }
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