C# Winform中执行post操作并获取返回的XML类型的数据
时间:2014-04-30 15:19:10
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/// <summary> /// 返回指定日期的订单数据 /// </summary> /// <param name="StartDate">起始日期</param> /// <param name="EndDate">结束日期</param> /// <returns>DataTable</returns> public System.Data.DataTable GetOrderDt(DateTime StartDate, DateTime EndDate) { try { dllEncrypt des = new dllEncrypt(); string strStartDate = des.Get_Time_String(StartDate); string strEndDate = des.Get_Time_String(EndDate); WebClient web = new WebClient(); //设置post的参数 System.Collections.Specialized.NameValueCollection PostData = new System.Collections.Specialized.NameValueCollection(); PostData.Add("stime", strStartDate);//将textBox1中的数据变为用a标识的参数,并用POST传值方式传给网页 PostData.Add("etime", strEndDate); //获取返回的数据 byte[] byRemoteInfo = web.UploadValues(GetUrl(), "POST", PostData); string sRemoteInfo = System.Text.Encoding.UTF8.GetString(byRemoteInfo); //读取字符串中的信息 StringReader StrStream = new StringReader(sRemoteInfo); //获取StrStream中的数据并存储为XML类型数据 XmlTextReader Xmlrdr = new XmlTextReader(StrStream); DataSet dss = new DataSet(); //将数据存储到数据集中 dss.ReadXml(Xmlrdr); if (dss.Tables != null && dss.Tables.Count > 0) { return dss.Tables[0]; } else { return null; } } catch (Exception ex) { return null; } }
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