《Cracking the Coding Interview》——第17章:普通题——题目13
时间:2014-04-29 14:51:49
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2014-04-29 00:15
题目:将二叉搜索树展开成一个双向链表,要求这个链表仍是有序的,而且不能另外分配对象,就地完成。
解法:Leetcode上也有,递归解法。
代码:
1 // 17.13 Flatten a binary search tree into a doubly linked list by inorder traversal order. 2 // Use postorder traversal to do the flattening job. 3 #include <cstdio> 4 using namespace std; 5 6 struct TreeNode { 7 int val; 8 TreeNode *left; 9 TreeNode *right; 10 TreeNode(int _val = 0): val(_val), left(nullptr), right(nullptr) {}; 11 }; 12 13 void flatten(TreeNode *&root, TreeNode *&left_most, TreeNode *&right_most) 14 { 15 if (root == nullptr) { 16 left_most = right_most = nullptr; 17 return; 18 } 19 20 TreeNode *ll, *lr, *rl, *rr; 21 if (root->left != nullptr) { 22 flatten(root->left, ll, lr); 23 root->left = lr; 24 lr->right = root; 25 } else { 26 ll = lr = root; 27 } 28 29 if (root->right != nullptr) { 30 flatten(root->right, rl, rr); 31 root->right = rl; 32 rl->left = root; 33 } else { 34 rl = rr = root; 35 } 36 37 left_most = ll; 38 right_most = rr; 39 } 40 41 void constructBinaryTree(TreeNode *&root) 42 { 43 int val; 44 45 if (scanf("%d", &val) != 1) { 46 root = nullptr; 47 } else if (val == 0) { 48 root = nullptr; 49 } else { 50 root = new TreeNode(val); 51 constructBinaryTree(root->left); 52 constructBinaryTree(root->right); 53 } 54 } 55 56 void deleteList(TreeNode *&head) 57 { 58 TreeNode *ptr; 59 60 while (head != nullptr) { 61 ptr = head; 62 head = head->right; 63 delete ptr; 64 } 65 } 66 67 int main() 68 { 69 TreeNode *root; 70 TreeNode *left_most, *right_most; 71 TreeNode *head; 72 TreeNode *ptr; 73 74 while (true) { 75 constructBinaryTree(root); 76 if (root == nullptr) { 77 break; 78 } 79 flatten(root, left_most, right_most); 80 head = left_most; 81 for (ptr = head; ptr != nullptr; ptr = ptr->right) { 82 printf("%d ", ptr->val); 83 } 84 putchar(‘\n‘); 85 deleteList(head); 86 } 87 88 return 0; 89 }
《Cracking the Coding Interview》——第17章:普通题——题目13,码迷,mamicode.com
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