《Cracking the Coding Interview》——第17章:普通题——题目5
时间:2014-04-29 17:10:21
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2014-04-28 22:44
题目:猜数字游戏。四个数字,每个都是0~9之间。你每猜一次,我都告诉你,有多少个位置和数字都对(全对),有多少个位置错数字对(半对)。比如“6309”,你猜“3701”,就有1全对,1半对。
解法:依照题意写就可以了。
代码:
1 // 17.5 I am the Master Mind. Guess the number. 2 // When you guessed the right number at the right position, you got a hit. 3 // When you guessed the right number at the wrong position, you got a pseudo-hit. 4 #include <cstdio> 5 using namespace std; 6 7 void check(int solution[], int guess[], int &hit, int &pseudo_hit) 8 { 9 static int c[4]; 10 static int mark[4]; 11 12 int i; 13 for (i = 0; i < 4; ++i) { 14 c[i] = 0; 15 mark[i] = 0; 16 } 17 18 hit = pseudo_hit = 0; 19 for (i = 0; i < 4; ++i) { 20 if (solution[i] == guess[i]) { 21 // hit 22 mark[i] = 1; 23 ++hit; 24 } else { 25 ++c[solution[i]]; 26 } 27 } 28 for (i = 0; i < 4; ++i) { 29 if (mark[i]) { 30 continue; 31 } 32 // pseudo_hit 33 if (c[guess[i]] > 0) { 34 mark[i] = 2; 35 --c[guess[i]]; 36 ++pseudo_hit; 37 } 38 } 39 } 40 41 int main() 42 { 43 int solution[4]; 44 int guess[4]; 45 int hit, pseudo_hit; 46 int i; 47 48 while (scanf("%d", &solution[0]) == 1) { 49 for (i = 1; i < 4; ++i) { 50 scanf("%d", &solution[i]); 51 } 52 for (i = 0; i < 4; ++i) { 53 scanf("%d", &guess[i]); 54 } 55 check(solution, guess, hit, pseudo_hit); 56 printf("%d hit(s), %d pseudo-hit(s).\n", hit, pseudo_hit); 57 } 58 59 return 0; 60 }
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