【原】sql 查询结果合为一行

SELECT COUNT(*) AS AllCount,t.AssignedCount,(COUNT(*)-t.AssignedCount) AS UnassignedCount
FROM 药品表
jOIN
(
SELECT COUNT(*) AS AssignedCount
FROM 质量分析分配表 
)as t on 1=1
group by t.AssignedCount

【原】sql 查询结果合为一行,布布扣,bubuko.com