IOS开发之——使用SBJson拼接Json字符串

时间：2014-05-07 03:22:16 收藏：0 阅读：426

SBJson包的下载地址在上一篇文章中。

可以使用NSDictionary中的键值对来拼接Json数据，非常方便，也可以进行嵌套，直接上代码：

    //开始拼接Json字符串
    NSDictionary *dataDictionary= [NSDictionary dictionaryWithObjectsAndKeys:@"mac",@"mac",
                                   @"game",@"game",
                                   @"devicetoken",@"devicetoken",
                                   @"device",@"device",
                                   @"gv",@"gv",
                                   @"lang",@"lang",
                                   @"os",@"os",nil];
    NSDictionary *parmDictionary= [NSDictionary dictionaryWithObjectsAndKeys:@"getSession",@"act",
                                   dataDictionary,@"data",nil];
    NSDictionary *jsonDictionary=[NSDictionary dictionaryWithObjectsAndKeys:@"pv",@"pv",
                                  parmDictionary,@"param",nil];
    SBJsonWriter *writer = [[SBJsonWriter alloc] init];
    
    NSString *jasonString = [writer stringWithObject:jsonDictionary];
    NSLog(@"%@",jasonString);

上面的代码用到了三层嵌套，注意的是，NSDictionary中，前面的是值，后面的是键。

拼接后的结果如下：

{"pv":"pv","param":{"act":"getSession","data":{"os":"os","mac":"mac","game":"game","gv":"gv","lang":"lang","devicetoken":"devicetoken","device":"device"}}}

使用Json在线校验工具解析后：

{
    "pv": "pv",
    "param": {
        "act": "getSession",
        "data": {
            "os": "os",
            "mac": "mac",
            "game": "game",
            "gv": "gv",
            "lang": "lang",
            "devicetoken": "devicetoken",
            "device": "device"
        }
    }
}

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