ProjectEuler_P11

时间:2014-05-06 14:35:55   收藏:0   阅读:460

Problem:

In the 20bubuko.com,布布扣20 grid below, four numbers along a diagonal line have been marked in red.

08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08
49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00
81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65
52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91
22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80
24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50
32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70
67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21
24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72
21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95
78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92
16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57
86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58
19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40
04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66
88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69
04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36
20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16
20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54
01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48

The product of these numbers is 26 bubuko.com,布布扣 63 bubuko.com,布布扣 78 bubuko.com,布布扣 14 = 1788696.

What is the greatest product of four adjacent numbers in the same direction (up, down, left, right, or diagonally) in the 20bubuko.com,布布扣20 grid?

思路:

考虑一行、一列、左斜、右斜四中情况;

C Code:

bubuko.com,布布扣
#include <stdio.h>
#define ROW 20
#define COL 20
#define NUM 4

int GetMaxOfRow(int iArray[][COL],int irow,int icol,int inum)
{
    int i,j;
    int max = 0;
    for(i = 0;i < irow;i++)
    {
        int tempMax = iArray[i][0] * iArray[i][1] * iArray[i][2] * iArray[i][3];
        for(j = 1;j < icol - inum;j++)
        {
            if(iArray[i][j + inum -1] > iArray[i][j-1])
            {
                int temp = iArray[i][j] * iArray[i][j + 1] * iArray[i][j + 2] * iArray[i][j + 3];
                if(temp > tempMax)
                {
                    tempMax = temp;
                }
            }
        }
        if(tempMax > max)
        {
            max = tempMax;
        }
    }
    return max;
}

int GetMaxOfCol(int iArray[][COL],int irow,int icol,int inum)
{
    int i,j;
    int max = 0;
    for(j = 0;j < icol;j++)
    {
        int tempMax = iArray[0][j] * iArray[1][j] * iArray[2][j] * iArray[3][j];
        for(i = 1;i < irow - inum;i++)
        {
            if(iArray[i + inum -1][j] > iArray[i-1][j])
            {
                int temp = iArray[i][j] * iArray[i + 1][j] * iArray[i + 2][j] * iArray[i + 3][j];
                if(temp > tempMax)
                {
                    tempMax = temp;
                }
            }
        }
        if(tempMax > max)
        {
            max = tempMax;
        }
    }
    return max;
}

int GetMaxOfLeftDiagonally(int iArray[][COL],int irow,int icol,int inum)
{
    int i,j;
    int max = 0;
    for(i = inum;i < irow;i++)
    {
        int tempMax = 0;
        for(j = 0;j < icol - inum;j++)
        {
            int temp = iArray[i][j] * iArray[i - 1][j + 1] * iArray[i - 2][j + 2] * iArray[i - 3][j + 3];

            if(temp > tempMax)
            {
                tempMax = temp;
            }
        }
        if(tempMax > max)
        {
            max = tempMax;
        }
    }
    return max;
}

int GetMaxOfRightDiagonally(int iArray[][COL],int irow,int icol,int inum)
{
    int i,j;
    int max = 0;
    for(i = 0;i < irow - inum;i++)
    {
        int tempMax = 0;
        for(j = 0;j < icol - inum;j++)
        {
            int temp = iArray[i][j] * iArray[i + 1][j + 1] * iArray[i + 2][j + 2] * iArray[i + 3][j + 3];

            if(temp > tempMax)
            {
                tempMax = temp;
            }
        }
        if(tempMax > max)
        {
            max = tempMax;
        }
    }
    return max;
}


void main()
{
    int iArray[ROW][COL];
    int i,j;
    int max1,max2,max3;
    for(i = 0;i < ROW;i++)
    {
        for(j = 0;j < COL;j++)
        {
            scanf("%d",&iArray[i][j]);
        }
    }
    max1 = GetMaxOfCol(iArray,ROW,COL,NUM);
    max2 = GetMaxOfRow(iArray,ROW,COL,NUM);
    max3 = max1 > max2? max1:max2;
    max1 = GetMaxOfLeftDiagonally(iArray,ROW,COL,NUM);
    max2 = GetMaxOfRightDiagonally(iArray,ROW,COL,NUM);
    max3 = max1 > max3? max1:max3;
    max3 = max2 > max3? max1:max3;
    printf("%d\n",max3);
}
bubuko.com,布布扣


Result:

70600674

ProjectEuler_P11,布布扣,bubuko.com

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